Q What could you reply to this

Nunn considered the following variations: 21 exf5 Sxe1+ 22 *xe1 ®xb2;

21 ftdl ±xe4! 22 £ixf2 (22 Wxe4 2xe4 23 £lxf2 Hxe1 + 24 £>xe1 Axf2) 22..Axb1;

21 2e2 ±xe4! 22 WcV. (22 Sxf2 Axb1; 22 £>xd4 &xg2 mate; 22 Sxe4 2xe4) 22...i.xf3! (weaker is 22...Wxf3 23 gxf3 l.xf3+ 24 Ig2+

However, later in analysis he found the successful defence 21 i.a1!?, parrying

Black's threats. He now has either to exchange on c3, which he would like to avoid, or play 21...ih3! 22 2g1 £g4, transposing into positions examined earlier, but with the bishop at a1 instead of b2.

Another, possibly even stronger reply was suggested by Zaitsev: 21 2f1! .&xe4 22 ^xe4 ®xb2, and now not 23 £ixd4? Wxb1

24 £tf6+ &g7 25 <£\xe8+ 2xe8 26 2xb1 cxd4 with a difficult rook ending for White, but 23 Wd3! According to Nunn, it was this move that he overlooked during the game. In view of the threats of 24 <£>eg5 and 24 4^xd6 White retains reasonable compensation for the sacrificed exchange. For example: 23...Sad8 24 <5teg5 (bad is 24 2b1? *xa2 25 ^xd4 2xe4 26 £M5 ®xb1 + 27 Ifxbl 2de8) 24...2e7? (24..Ag7 is better)

25 Wxh7+ 4*8 26 £>e5!, or 23...£g7 24 £>xd6 2e2 (24...fTe2 25 «b1) 25 <£g5 Wc2

But now let us return to the game. Since 20...i.xc3? 21 Wxc3 will not do, there remains only one way for Black to save his queen.

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