G

anything else would result in catastrophe. 41 . . . P xN 42 RxB Q-N7 + (372) 43 K-Bl PxP 44 R-KN5 +

•J—i There is nothing left after 44 . . . K-R3 45QxN+ KXR46Q-K7 + and then 47 Q xKP.

3106 AK-Lev Polugayevsky: G6:

Sicilian

1 P-K4 P-QB4 2 N-KB3 P-Q.3 3 P-Q4 PxP 4 NxP N-KB3 5 N-QB3 P-QR3 6 B-K2 P-K4 7 N-N3 B-K2 8 0-0 B-K3 9 P-B4 Q B2 10 P-QR4 QN-Q2 11 K-Rl 0-0 12 B-K3 PxP 13 RxP N-K4 thus far as in the fourth game 14 P-R5! much better than 14 N-Q4 14... N3-Q2 15 R-KB1B-B3 (373)

only eases Black's task. 17 . . . QxBP! otherwise Black has few prospects. 18 N-Q4 QxNP 19 QR-N1 Q-B6 20 N-B5 Q-B7 21 R/N1-K1 N-B4 if 21 ... Q-B3, to exchange queens, then 22 NxQP with an excellent game for White -he will always be able to pick up the QNP and then it would be difficult for Black to defend his QRP. 22 N X QP N/B4-Q6 23 B x N N x B 24 R-Ql N-N5 25 Q x NP?J Vasyukov prefers 25 Q-KB5 or 25 Q-R5 keeping the initiative. 25 ... QR-N1 26 Q-R7 (374)

26 . . . Q-B3? 26 . . . Q-K7!, as suggested by Shatskes, is correct, when it is very difficult for White's rooks to leave the back rank and Black threatens 27 . . . N-Q6 (or

27 . . . N-B3) followed by 28 . . . R-N7. And on 27 R/Q1-K1 Black would have the choice of 27 . . . Q-R4 (or 27 . . . Q-N5) and 27 . . . Q-R7. 27 B-B4. There was also a possibility of 27 RxB PxR 28 B-R6, discovered by Furman in the press room, but then White would have to reckon with the possibility of 28 . . . Q-B7 e.g. 29 Q-Q4? N-Q6! or 29 R-QB1 Q-Q6 30 Q-K7 Q-Q5. Karpov prefers to strengthen his position. 27 ... R-Rl

28 Q-B2 QR-Q129 Q-N3 Q-B6 30 R-B3 Q-B7 31 R1-KB1 B-Q5 32 B-R6 N-B3 33 N-B5 Q.-N7 if 33 . . . B-K4 then 34 BxP wins as Karpov pointed out in the postmortem: 34 ... B xQ 35 RxB P-R4 (the threat was 36 N-R6 mate) 36 B-B6+ K-R2 37 R-N7+ K-Rl 38 RxP+ K-Nl 39 N-R6 mate. 34 B-Bl! Q-N4 35 N-R6+ K-Rl 36 NxP+ RxN 37 RxR B-B3 38 Q-B2 K-Nl 39 RxB PxR 40 QxP 1-0

3107 Lev Polugayevsky AK: G7: Nimzo-Indian

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